document.write( "Question 694208: Sara leaves home at 7am traveling at a rate of 45 mi/h. her son discovers that she has forgotten her briefcase and starts out to catch up with her. her son leaves at 7:30 am traveling at a rate of 55 mi/h. At what time will he over take his mother? \n" ); document.write( "
Algebra.Com's Answer #427790 by mananth(16946)\"\" \"About 
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Sara 45 mph
\n" ); document.write( "Son 55 mph
\n" ); document.write( "Sara 07:00
\n" ); document.write( "Son 07:30
\n" ); document.write( "Difference in time= 00:30 => 0.50 hours
\n" ); document.write( "Sara will have covered 22.50 miles Son starts
\n" ); document.write( "catch up distance= 22.50 miles
\n" ); document.write( "catch up speed = 55 -45
\n" ); document.write( "catch up speed = 10 mph
\n" ); document.write( "Catchup time = catchup distance/catch up speed
\n" ); document.write( "catch up time= 2.25
\n" ); document.write( "catch up time= 2.25 hours
\n" ); document.write( "They will meet at 9:55 am mph
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