document.write( "Question 694167: area of a rectangle: A=LW\r
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document.write( "The are of this rectangle is 39 square units. Find its length (the horizontal side ) and width (the vertical side)\r
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document.write( "length)x+5
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document.write( "width) x-5\r
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document.write( "a) write an equation using the formula and the given information.
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document.write( "39=? (do not multiply)\r
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document.write( "b) solve the equation, giving only the solution(s) that make sense in the problem. The solution for x is ?\r
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document.write( "c) use the solution to find the indicated dimensions of the figure.
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document.write( "Length=? Width=? \n" );
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Algebra.Com's Answer #427777 by ShaunaJS(1)![]() ![]() ![]() You can put this solution on YOUR website! (x+5)(x-5)=39 \n" ); document.write( "x^2-5x+5x-25=39 \n" ); document.write( "x^2-25=39 \n" ); document.write( "x^2-64=0 \n" ); document.write( "x^2-8x+8x-64=0 \n" ); document.write( "x(x-8)+8(x-8)=0 \n" ); document.write( "(x-8)(x+8)=0 \n" ); document.write( "x-8=0 or x+8=0 \n" ); document.write( "x=8 or x=-8 \n" ); document.write( "8+5=13, 8-5=3, -8+5=-3, -8-5=-13 \n" ); document.write( "You can't have negatives as a length or width. \n" ); document.write( "So x=8 \n" ); document.write( "Length=8+5 \n" ); document.write( "Width=8-5 \n" ); document.write( "Length=13 \n" ); document.write( "Width=3 \n" ); document.write( " |