document.write( "Question 694174: find all 12 solutions to x^12=1
\n" ); document.write( "Already know 1 and -1 are solutions, but I'm not sure how to factor the equation.
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Algebra.Com's Answer #427775 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint: \r
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\n" ); document.write( "\n" ); document.write( "x^12=1\r
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\n" ); document.write( "\n" ); document.write( "x^12 - 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x^4)^3 - 1^3 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x^4 - 1)((x^4)^2 + x^4*1 + 1^2) = 0\r
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\n" ); document.write( "\n" ); document.write( "(x^4 - 1)(x^8 + x^4 + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "(x^2 - 1)(x^2 + 1)(x^8 + x^4 + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "(x - 1)(x + 1)(x^2 + 1)(x^8 + x^4 + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "Note: \r
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\n" ); document.write( "\n" ); document.write( "To solve x^8 + x^4 + 1 = 0, let z = x^4 to get z^2 + z + 1 = 0. Solve for z and use this to find solutions to x.
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