document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694069>Question 694069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(x-3)+log(x) = 2 + log(x+2) *The base for the logarithms is 2. I just need help clarifying my answer, I found that this problem had no solution but I'm not completely sure if that is correct </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427724 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(x-3)+log(x) = 2 + log(x+2) <BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "log[(x-3)x] - log(x+2) = 2<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "log[(x^2-3x)/(x+2)] = 2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(x^2-3x)/(x+2) = 2^2<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "x^2-3x = 4x+8<BR>\n" );
document.write( "x^2 - 7x - 8 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x-8)(x+1) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );