document.write( "Question 693979: process please:\r
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\n" ); document.write( "\n" ); document.write( "How many ml of a 30% acid solution must be mixed with 2 ml of a 40% acid solution to make a 32% solution?
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Algebra.Com's Answer #427671 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.30x+.40*2=.32(x+2)
\n" ); document.write( ".30x+.80=.32x+.64
\n" ); document.write( ".30x-.32x=.64-.80
\n" ); document.write( "-.02x=-.16
\n" ); document.write( "x=-.16/-.02
\n" ); document.write( "x=8 ml of the 30% solution is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".30*8+.40*2=.32(8+2)
\n" ); document.write( "2.4+.8=.32*10
\n" ); document.write( "3.2=3.2
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