document.write( "Question 693928: Simplify this quadratic answer\r
\n" ); document.write( "\n" ); document.write( "9+-√693 /3\r
\n" ); document.write( "\n" ); document.write( "( Just restating it incase it was hard to read ) 9 plus or minus the square root of 693 divided by 3 \n" ); document.write( "

Algebra.Com's Answer #427663 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
I believe that you meant $\"%289+%2B-+sqrt%28693%29%29%2F3\"$ which you could write as (9 +- sqrt(693))/3.
\n" ); document.write( "Since the digits of $\"693\"$ add to $\"18\"$ , which is a multiple of $\"9\"$ ,
\n" ); document.write( "we know that $\"693\"$ is a multiple of $\"9\"$ ,
\n" ); document.write( "so we divide to find $\"693%2F9=77\"$ <--> $\"693=9%2A77\"$ .
\n" ); document.write( "We also know that $\"sqrt%289%29=3\"$ .
\n" ); document.write( "We also know that $\"9=3%2A3\"$ .
\n" ); document.write( "So,
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\n" ); document.write( "
\n" ); document.write( "(If you meant 9 +- sqrt(693)/3 = $\"9+%2B-+sqrt%28693%29\"$ / $\"3\"$ = $\"9+%2B-+sqrt%28693%29%2F3\"$ , which is a different number, I am sorry to have misinterpreted). \n" ); document.write( "

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