document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=693921>Question 693921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of each of a 15% acid solution and a 75% acid solution must be used to to produce 90 liters of a 25% acid solution? ( round to two decimal places if necessary.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427628 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of each of a 15% acid solution and a 75% acid solution must be used to to produce 90 liters of a 25% acid solution? ( round to two decimal places if necessary.)<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.15x + 0.75(90-x_ = 0.25*90<BR>\n" );
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document.write( "15x + 75*90 - 75x = 25*90<BR>\n" );
document.write( "-80x = -50*90<BR>\n" );
document.write( "x = (5/8)90<BR>\n" );
document.write( "x = 56.25 liters (amt. 15% solution needed)<BR>\n" );
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document.write( "90-x + 33.75 liters (amt. of 75% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
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