document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=693900>Question 693900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has its center at (2,-1) and one of a diameter at(5,1).Find the other end of the diameter.<BR>\n" );
document.write( "Pls answer this..tnx. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427622 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circle has its center at (2,-1) and one end of a diameter is at(5,1).<BR>\n" );
document.write( "Find the other end of the diameter.<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Let the other end be (x,y)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Solve for x and for y:<BR>\n" );
document.write( "(x+5)/2 = 2<BR>\n" );
document.write( "x+5 = 4<BR>\n" );
document.write( "x = -1<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "(y+1)/2 = -1<BR>\n" );
document.write( "y+1 = -2<BR>\n" );
document.write( "y = -3<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Other end: (-1,-3)<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );