document.write( "Question 693828: how many liters of water must be added to 10 liters of a 95% acid solution to make an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #427565 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=amount of water that must be added
\n" ); document.write( "Now we know that the amount of pure acid before the water is added (0.95*10) has to equal the amount of pure acid after the water is added(0.80(10+x)). Sooooo
\n" ); document.write( "0.80(10+x)=0.95*10
\n" ); document.write( "8+0.80x=9.5
\n" ); document.write( "0.80x=1.5
\n" ); document.write( "x=1.875 liters=1 7/8 liter---amount of water that needs to be added\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "0.95*10=0.80*11.875
\n" ); document.write( "9.5=9.5\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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