document.write( "Question 62022: The perimeter of a rectangle is 82 yards. The width is 15 yardsless than the length. Find the length and width of the rectangle.\r
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Algebra.Com's Answer #42755 by DJ_Sammie(24)![]() ![]() ![]() You can put this solution on YOUR website! l=length \n" ); document.write( "l-15=width \n" ); document.write( " 2l+2w=P \n" ); document.write( "p=perimeter \n" ); document.write( "2l+2(l-15)=82 \n" ); document.write( "2l+2l-30=82 \n" ); document.write( "4l-30=82 \n" ); document.write( " +30 +30 \n" ); document.write( " 4l=112 \n" ); document.write( " 4l/4=112/4 \n" ); document.write( " l=28 \n" ); document.write( "length=28yards \n" ); document.write( "width=l-15 \n" ); document.write( "width=28-15 \n" ); document.write( "width=13yards \n" ); document.write( "The width is 13 yards and the length is 28 yards. \n" ); document.write( " |