document.write( "Question 693647: 2x^3-13x^2+24x-9=0 \r
\n" ); document.write( "\n" ); document.write( "How do I find zeros?
\n" ); document.write( "

Algebra.Com's Answer #427517 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
Any rational zeros would be of the form \"p%2Fq\",
\n" ); document.write( "with \"p\" being a factor of the constant (\"-9\"),
\n" ); document.write( "and \"q\" being a factor of the leading coefficient (\"2\")
\n" ); document.write( "Factors of \"9\" are 1, 3, and 9.
\n" ); document.write( "Factors of \"2\" are 1, and 2.
\n" ); document.write( "Possible rational zeros are -1/2, -3/2, -9/2, -1, -3, -9, 1/2, 3/2, 9/2, 1, 3, and 9.
\n" ); document.write( "Descartes rule of signs helps narrow down your choices.
\n" ); document.write( "\"P%28x%29=2x%5E3-13x%5E2%2B24x-9\" has 3 changes of sign going from one coefficient to the next. That means that it has 3 or 1 positive zeros. (It could be two different zeros if one is a double zero).
\n" ); document.write( "\"P%28-x%29=-2x%5E3-13x%5E2-24x-9\" has 0 changes of sign, meaning that there are 0 negative zeros.
\n" ); document.write( "Now we say that possible rational zeros are 1/2, 3/2, 9/2, 1, 3, and 9.
\n" ); document.write( "Trying the possible zeros, using synthetic division, we find out that
\n" ); document.write( "\"2x%5E3-13x%5E2%2B24x-9=%282x-1%29%28x%5E2-6x%2B9%29\"
\n" ); document.write( "Then we recognize that \"x%5E2-6x%2B9=%28x-3%29%5E2\" and have the complete factorization,
\n" ); document.write( "\"2x%5E3-13x%5E2%2B24x-9=%282x-1%29%28x-9%29%5E2\",
\n" ); document.write( "which tells us that the zeros are \"highlight%283%29\" (with multiplicity 2, a double zero), and \"highlight%281%2F2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );