document.write( "Question 693710: the cube root of 8x to the 3rd-1 = 2x-1\r
\n" ); document.write( "\n" ); document.write( "i already tried cubing both sides of the equation to get rid of the radical then then i was left with:\r
\n" ); document.write( "\n" ); document.write( "8x to the 3rd -1= 8x to the 3rd -12x to the 2nd +6x-1
\n" ); document.write( " this is where i got stuck what did i do wrong above?
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Algebra.Com's Answer #427506 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
\"root%283%2C8x%5E3-1%29+=+2x-1\"
\n" ); document.write( "...
\n" ); document.write( "\"root%283%2C8x%5E3-1%29%5E3+=+%282x-1%29%5E3\"
\n" ); document.write( "8x^3-1 = (2x-1)^3
\n" ); document.write( "...
\n" ); document.write( "(2x-1)^3 = (2x-1)(4x^2-4x+1)
\n" ); document.write( "8x^3-8x^2+2x-4x^2+4x-1
\n" ); document.write( "8x^3-12x^2+6x-1
\n" ); document.write( "...
\n" ); document.write( "8x^3 - 1 = 8x^3 - 12x^2 + 6x - 1
\n" ); document.write( "0 = 8x^3 - 8x^3 - 12x^2 + 6x - 1 + 1
\n" ); document.write( "0 = -12x^2 + 6x
\n" ); document.write( "0 = -6x(2x-1)
\n" ); document.write( "0 = 2x-1
\n" ); document.write( "2x = 1
\n" ); document.write( "x = \"1%2F2\"
\n" ); document.write( "and
\n" ); document.write( "x = 0
\n" ); document.write( "...
\n" ); document.write( "You did not make any errors, you just needed to keep going!
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