document.write( "Question 693546: loga(x^2)-loga(x+1)=loga(x-3) \n" ); document.write( "
Algebra.Com's Answer #427457 by mouk(232)\"\" \"About 
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\"+log%28a%2Cx%5E2%29-log%28a%2Cx%2B1%29=log%28a%2Cx-3%29+\"
\n" ); document.write( "\"+log%28a%2C%28x%5E2%29%2F%28x%2B1%29%29=log%28a%2Cx-3%29+\"
\n" ); document.write( "\"+%28x%5E2%29%2F%28x%2B1%29=x-3+\"
\n" ); document.write( "\"+x%5E2=%28x-3%29%28x%2B1%29+\"
\n" ); document.write( "\"+x%5E2=x%5E2-2x-3+\"
\n" ); document.write( "\"+0=-2x-3+\"
\n" ); document.write( "\"+2x=-3+\"
\n" ); document.write( "\"+x=-3%2F2+\"
\n" ); document.write( "
\n" );