document.write( "Question 693487: \r
\n" ); document.write( "\n" ); document.write( " What quantity of 70 per cent acid solution must be mixed with a 15 percent solution to produce 4 mL of a 30 per cent solution?
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Algebra.Com's Answer #427446 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.70X+.15(4-X)=.30*4
\n" ); document.write( ".70X+.60-.15X=1.20
\n" ); document.write( ".55X=1.20-.60
\n" ); document.write( ".55X=.60
\n" ); document.write( "X=.60/.55
\n" ); document.write( "X=1.09 ML OF THE 70% SOLUTION IS USED.
\n" ); document.write( "4-1.09=2.91 ML OF THE 15% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".70*1.09+.15*2.91=1.20
\n" ); document.write( ".763+.436=1.20
\n" ); document.write( "1.1995=1.20\r
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