document.write( "Question 693487: \r
\n" ); document.write( "\n" ); document.write( " What quantity of 70 per cent acid solution must be mixed with a 15 percent solution to produce 4 mL of a 30 per cent solution? \n" ); document.write( "

Algebra.Com's Answer #427445 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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What quantity of 70 per cent acid solution must be mixed with a 15 percent solution to produce 4 mL of a 30 per cent solution?
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\n" ); document.write( "Let x = quantity of 70% solution required
\n" ); document.write( "then resulting total amt is 4, therefore:
\n" ); document.write( "(4-x) = quantity of 15% solution
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\n" ); document.write( ".70x + .15(4-x) = .30(4)
\n" ); document.write( ".70x + .6 - .15x = 1.2
\n" ); document.write( ".70x - .15x = 1.2 - .6
\n" ); document.write( ".55x = .6
\n" ); document.write( "x = .6/.55
\n" ); document.write( "x ~ 1.1 liters of 70% solution required
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\n" ); document.write( "Check this
\n" ); document.write( ".7(1.1) + .15(4-1.1) = .3(4)
\n" ); document.write( ".77 + .435 = 1.2 \n" ); document.write( "

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