document.write( "Question 693405: A logging barge on the Mississippi River travels 24 miles upstream in 3 hours. The return trip take the barge only 2 hours. Find the rate of the barge in still water. \n" ); document.write( "
Algebra.Com's Answer #427381 by pmatei(79)\"\" \"About 
You can put this solution on YOUR website!
Speed is distance divided by time. \r
\n" ); document.write( "\n" ); document.write( "Going upstream slows you down by the speed of the river\r
\n" ); document.write( "\n" ); document.write( "\"v%5Bbarge%5D-v%5Briver%5D=%2824miles%29%2F%283hours%29=8mph\"\r
\n" ); document.write( "\n" ); document.write( "Going downstream you go faster:\r
\n" ); document.write( "\n" ); document.write( "\"v%5Bbarge%5D%2Bv%5Briver%5D=%2824miles%29%2F%282hours%29=12mph\"\r
\n" ); document.write( "\n" ); document.write( "If you add the two equations, \"v%5Briver%5D\" cancels and you get:\r
\n" ); document.write( "\n" ); document.write( "\"2v%5Bbarge%5D=20mph\"\r
\n" ); document.write( "\n" ); document.write( "\"v%5Bbarge%5D=10mph\"
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