document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=693278>Question 693278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve the following equation log[9](5x-3)- log[3]2&#8730;x =0. Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427361 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the following equation log[9](5x-3)- log[3]2&#8730;x = 0<BR>\n" );
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document.write( "log9(5x-3) - [log9[2sqrt(x)]]/log9(3) = 0<BR>\n" );
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document.write( "log9(5x-3) - [log9(2sqrt(x)]/(1/2) = 0<BR>\n" );
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document.write( "log9(5x-3) - log9(4x) = 0<BR>\n" );
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document.write( "log[(5x-3)/4x = 0<BR>\n" );
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document.write( "(5x-3)/4x = 1<BR>\n" );
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document.write( "5x-3 = 4x<BR>\n" );
document.write( "x = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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