document.write( "Question 693167: The units digit of a two digit number is 1 more than twice the tens digit. If the digits are reversed,the new number is 36 more than the original number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #427323 by rimjhim.tomar(21)\"\" \"About 
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let the tens digit be x
\n" ); document.write( "hence units digit would be 2x+1
\n" ); document.write( "and the two digit number would be =10(tens digit)+unit digit
\n" ); document.write( "=10(x)+2x+1
\n" ); document.write( "now,
\n" ); document.write( "when the digits are reversed,
\n" ); document.write( "we have-
\n" ); document.write( "the tens digit of the new number=(unit digit of the original number)= 2x+1
\n" ); document.write( "and similarly,unit digit of the new number=x
\n" ); document.write( "hence the new number=10(2x+1)+x
\n" ); document.write( "given that-
\n" ); document.write( "the new number is 36 more than the original number
\n" ); document.write( "or
\n" ); document.write( "10(x)+2x+1+36=10(2x+1)+x
\n" ); document.write( "10x+2x+1+36=20x+10+x
\n" ); document.write( "12x+37=21x+10
\n" ); document.write( "12x-21x=10-37
\n" ); document.write( "-9x=-27
\n" ); document.write( "x=(-27)/(-9)
\n" ); document.write( "x=3\r
\n" ); document.write( "\n" ); document.write( "the number= 10(x)+2x+1
\n" ); document.write( "=10(3)+2(3)+1
\n" ); document.write( "=30+6+1
\n" ); document.write( "=37 \n" ); document.write( "
\n" );