document.write( "Question 693184: Tom is 3 years older than Mary and Jane is 5 years older than Tom. What is the average age?
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Algebra.Com's Answer #427319 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Tom is 3 years older than Mary and Jane is 5 years older than Tom. What is the average age?\r
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\n" ); document.write( "\n" ); document.write( "Let Mary's age be M
\n" ); document.write( "Then Tom's is: M + 3, and Jane's is: M + 3 + 5, or M + 8\r
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\n" ); document.write( "\n" ); document.write( "Sum of their ages = M + M + 3 + M + 8, or 3M + 11\r
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\n" ); document.write( "\n" ); document.write( "Average age = \"highlight_green%28%283M+%2B+11%29%2F3%29\", or \"highlight_green%28M+%2B+11%2F3%29\"\r
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