document.write( "Question 61996: Subtract.4 1/3-1 1/4 \n" ); document.write( "
Algebra.Com's Answer #42731 by Edwin McCravy(20060) $\"\"$ $\"About$
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document.write( "4 1/3-1 1/4 \r\n" );
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document.write( "Write them vertically like this\r\n" );
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document.write( " 4 1/3\r\n" );
document.write( "-1 1/4 \r\n" );
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document.write( "Get the LCD of 3 and 4. Since they have no common\r\n" );
document.write( "factors other than 1, the LCD is their product, 12.\r\n" );
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document.write( "To start, we need to change the 1/3 to something \r\n" );
document.write( "over 12.\r\n" );
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document.write( "Notice that the denominator of 1/3, which is 3,\r\n" );
document.write( "needs to be multiplied by 4 to become 12. So \r\n" );
document.write( "multiply both the denominator and numerator by 4.\r\n" );
document.write( "That gives you a numerator of 4 and a denominator \r\n" );
document.write( "of 12.  So put an equal sign after 4 1/3 and put \r\n" );
document.write( "4 4/12 after it, like this\r\n" );
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document.write( "  4 1/3 =  4 4/12  \r\n" );
document.write( " -1 1/4   \r\n" );
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document.write( "Now we need to change 1/4 to something over 12.\r\n" );
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document.write( "Notice that the denominator of 1/4, which is 4,\r\n" );
document.write( "needs to be multiplied by 3 to become 12. So \r\n" );
document.write( "multiply both the denominator and numerator by 3.\r\n" );
document.write( "That gives you a numerator of 3 and a denominator \r\n" );
document.write( "of 12.  So put an equal sign after -1 1/4 and put \r\n" );
document.write( "1 3/12 after it, like this \r\n" );
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document.write( "  4 1/3 =   4 4/12  \r\n" );
document.write( " -1 1/4 =  -1 3/12\r\n" );
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document.write( "Now we draw a line underneath like this\r\n" );
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document.write( "  4 1/3 =   4 4/12  \r\n" );
document.write( " -1 1/4 =  -1 3/12\r\n" );
document.write( "          ---------\r\n" );
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document.write( "Now we subtract the whole parts: 4 - 1 = 3\r\n" );
document.write( "and we subtract only the numerators of the\r\n" );
document.write( "fractions, 4-1, getting a numerator of 3,\r\n" );
document.write( "keeping the denominator of 12, like this:\r\n" );
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document.write( "  4 1/3 =   4 4/12  \r\n" );
document.write( " -1 1/4 =  -1 3/12\r\n" );
document.write( "          ---------\r\n" );
document.write( "            3 1/12\r\n" );
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document.write( "When the numerator of the top fraction is\r\n" );
document.write( "smaller than numerator of the bottom\r\n" );
document.write( "fraction, you have to do something else,\r\n" );
document.write( "but that wasn't required here.\r\n" );
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document.write( "Edwin
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