document.write( "Question 692583: David is 1/4 mile from home bicycling at 21 mph when his brother takes off on his bike from home trying to catch him. How fast must David’s brother go to catch David a mile from home? \n" ); document.write( "
Algebra.Com's Answer #427245 by ankor@dixie-net.com(22740)\"\" \"About 
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David is 1/4 mile from home bicycling at 21 mph, when his brother takes off on his bike from home trying to catch him.
\n" ); document.write( " How fast must David’s brother go to catch David a mile from home?
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\n" ); document.write( "Brother has to ride 1 mile while David rides 3/4 of a mile (use .75 mi)
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\n" ); document.write( "Let s = brothers required speed, to accomplish this
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\n" ); document.write( "Write a time equation, time = dist/speed
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\n" ); document.write( "\".75%2F21\" = \"1%2Fs\"
\n" ); document.write( "cross multiply
\n" ); document.write( ".75s = 1 * 21
\n" ); document.write( "s = \"21%2F.75\"
\n" ); document.write( "s = 28 mph
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\n" ); document.write( "Find the times, should be equal
\n" ); document.write( "1/28 = .0357 hrs
\n" ); document.write( ".75/21 = .0357
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