document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61902>Question 61902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi you guys, i need help with this question for sat or sunday, thank you very much.\r<BR>\n" );
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document.write( "Find the distance from the point Q(-3,-3,-4) to the line which passes through the point P(3,3,-4) and is parallel to the line whose equation is:\r<BR>\n" );
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document.write( "(x,y,z) = (-7,1,-2) + t(-1,-2,2).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42723 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING EXAMPLE AND DO.IT IS EXACTLY SIMILAR PROBLEM.<BR>\n" );
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document.write( "Find the distance from the point Q(-3,-3,-8) to the line which passes through the point P(-7,-7,2) and is parallel to the line(L SAY) whose equation is:<BR>\n" );
document.write( "(x,y,z) = (-3,-1,0) + t(2,2,-2).<BR>\n" );
document.write( "Thank you!<BR>\n" );
document.write( "EQN.OF LINE THROUGH P AND PARALLEL TO L IS<BR>\n" );
document.write( "R=(-7,-7,2)+T(2,2,-2)=i(-7+2T)+j(-7+2T)+k(2-2T)<BR>\n" );
document.write( "LET,R BE A POINT ON LINE L SUCH THAT QR IS PERPENDICULAR TO L FOR A<BR>\n" );
document.write( "PARTICULAR T<BR>\n" );
document.write( "VECTOR QR = R-Q = i(-7+2T+3)+j(-7+2T+3)+k(2-2T+8)<BR>\n" );
document.write( "QR = i(-4+2T)+j(-4+2T)+k(10-2T)<BR>\n" );
document.write( "IT IS PER PENDICULAR TO LINE L WHOSE DIRECTION VECTOR = D = 2i+2j-2k<BR>\n" );
document.write( "HENCE THEIR DOT PRODUCT SHOULD EQUAL ZERO<BR>\n" );
document.write( "D.QR = 2(-4+2T)+2(-4+2T)-2(10-2T)=0<BR>\n" );
document.write( "12T = 36<BR>\n" );
document.write( "T=3<BR>\n" );
document.write( "HENCE QR = 2i+2j+4k<BR>\n" );
document.write( "|QR|=SQRT(2^2+2^2+4^2)=SQRT(24)=2SQRT(6)<BR>\n" );
document.write( "HENCE PERPENDICULAR DISTANCE = 2SQRT(6)  </SPAN>\n" );
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