document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=693026>Question 693026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "One number is 4 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 286, find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427222 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X BE THE FIRST NUMBER.<BR>\n" );
document.write( "4X IS THE NEXT NUMBER.<BR>\n" );
document.write( "X=100 IS THE NEXT NUMBER.<BR>\n" );
document.write( "X+4X+X+100=286<BR>\n" );
document.write( "6X=286-100<BR>\n" );
document.write( "6X=186<BR>\n" );
document.write( "X=186/6<BR>\n" );
document.write( "X=31 ANS. FOR THE FIRST NUMBER.<BR>\n" );
document.write( "4*31=124 ANS. FOR THE NEXT NUMBER.<BR>\n" );
document.write( "31+100=131 ANS. FOR THE NEXT NUMBER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "31+124+131=286<BR>\n" );
document.write( "286=286 </SPAN>\n" );
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