document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=692936>Question 692936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "The larger of two supplementary angles is 20° less than four times the smaller find the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427213 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=4Y-20<BR>\n" );
document.write( "X+Y=180<BR>\n" );
document.write( "(4Y-20)+Y=180<BR>\n" );
document.write( "5Y=180+20<BR>\n" );
document.write( "5Y=200<BR>\n" );
document.write( "Y=200/5<BR>\n" );
document.write( "Y=40 DEGREES FOR THE SMALLER ANGLE. <BR>\n" );
document.write( "X=4*40-20<BR>\n" );
document.write( "Y=160-20<BR>\n" );
document.write( "Y=140 DEGREES FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "40+140=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
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