document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=692980>Question 692980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
document.write( "\n" );
document.write( "The sum of the digits of a two digit number is seven. When the digits are reversed, the number is increased by 27. Find the number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427205 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=7 OR X=7-Y<BR>\n" );
document.write( "10X+Y=10Y+X-27 REPLACE X WITH (7-Y) * SOLVE FOR Y.<BR>\n" );
document.write( "10(7-Y)+Y=10Y+(7-Y)-27<BR>\n" );
document.write( "70-10Y+Y=10Y+7-Y-27<BR>\n" );
document.write( "-10Y-10Y+Y+Y=7-27-70<BR>\n" );
document.write( "-18Y=-90<BR>\n" );
document.write( "Y=-90/-18<BR>\n" );
document.write( "Y=5 ANS FOR THE 10'S DIGIT OF THE ORIGINAL NUMBER.<BR>\n" );
document.write( "X+5=7<BR>\n" );
document.write( "X=7-5=2 ANS. FOR THE UNITS DIGIT IN THE ORIGINAL NUMBER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "52-25=27<BR>\n" );
document.write( "27=27 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );