document.write( "Question 61617: Find the slope of the line perpendicular to the line passing through the poings p(6,-1) abd Q(3,-2)\r
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Algebra.Com's Answer #42720 by ankor@dixie-net.com(22740)\"\" \"About 
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Find the slope of the line perpendicular to the line passing through the points p(6,-1) abd Q(3,-2) \r
\n" ); document.write( "\n" ); document.write( "Slope of line PG =_____slope of perpendicular
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\n" ); document.write( "First find the slope of the line PQ: Use slope formula: m = (y2-y1)/(x2-x1)
\n" ); document.write( "PQ points: x1 = 6; y1 = -1; x2 = 3; y2 = -2
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\n" ); document.write( "m1 = \"%28-2-%28-1%29%29%2F%283-6%29\" = \"%28-2%2B1%29%2F-3\" = \"%28-1%29%2F%28-3%29\" = +1/3 is the slope of line PQ
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\n" ); document.write( "Call the slope of line perpendicular to PQ, m2:
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\n" ); document.write( "Perpendicular line slopes relationship: m1*m2 = -1
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\n" ); document.write( "(1/3)*m2 = -1
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\n" ); document.write( "m2 = -1/(1/3)
\n" ); document.write( "m2 = -1*(3/1)
\n" ); document.write( "m2 = -3 is the slope of the perpendicular line
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\n" ); document.write( "did this make sense to you
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