document.write( "Question 692935: suppose you want to find two consecutive integers such that the sum of their squares is 613. what are they? \n" ); document.write( "

Algebra.Com's Answer #427189 by htmentor(1343) $\"\"$ $\"About$

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Let the two integers be n and n+1
\n" ); document.write( "n^2 + (n+1)^2 = 613
\n" ); document.write( "n^2 + n^2 + 2n + 1 = 613
\n" ); document.write( "2n^2 + 2n - 612 = 0
\n" ); document.write( "n^2 + n - 306 = 0
\n" ); document.write( "This can be factored as:
\n" ); document.write( "(n-17)(n+18) = 0
\n" ); document.write( "This gives n = 17, n = -18
\n" ); document.write( "So there are two possible solutions: 17, 18 and -18, -17 \n" ); document.write( "

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