document.write( "Question 691661: Can you help me find the vertex, focus, and equation of the directrix for x^2 =12y?
\n" ); document.write( "From what I worked out I think the vertex is (0,0); the focus (0,3); and the equation is x^2=4*3y.
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Algebra.Com's Answer #427153 by lwsshak3(11628)\"\" \"About 
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find the vertex, focus, and equation of the directrix for x^2 =12y?
\n" ); document.write( "This is an equation of a parabola that opens upwards
\n" ); document.write( "Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex, p=distance from vertex to focus or directrix on the axis of symmetry
\n" ); document.write( "For given equation: x^2=12y
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry:x=0 or y-axis
\n" ); document.write( "4p=12
\n" ); document.write( "p=3
\n" ); document.write( "focus: (0,3)
\n" ); document.write( "directrix: y=-3
\n" ); document.write( "you got everything right except the directrix which is just a horizontal straight line p-units below the vertex on the axis of symmetry
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