document.write( "Question 692842: I'm having difficulty with this problem:
\n" ); document.write( "A construction company builds a rectangular fenced in area with a perimeter of 46m. The length is 5m more than the width. Find the dimensions of the fence.\r
\n" ); document.write( "\n" ); document.write( "I know it's easy, but I can't remember how to do it.\r
\n" ); document.write( "\n" ); document.write( "This is what I tried:
\n" ); document.write( "2x+2y+5=46
\n" ); document.write( "

Algebra.Com's Answer #427106 by htmentor(1343)\"\" \"About 
You can put this solution on YOUR website!
Length is 5 more than the width:
\n" ); document.write( "L = W + 5
\n" ); document.write( "Perimeter = P = 2L + 2W = 2(W+5) = + 2W = 46
\n" ); document.write( "Solve for W:
\n" ); document.write( "W + 5 + W = 23
\n" ); document.write( "2W = 18
\n" ); document.write( "W = 9
\n" ); document.write( "So the width is 9 and the length is 14
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