document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=692705>Question 692705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of a parabola given focus (-2,3) directrix y=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427071 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation of a parabola given focus (-2,3) directrix y=-3<BR>\n" );
document.write( "This is a parabola that opens upwards.<BR>\n" );
document.write( "Its standard form of equation: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex<BR>\n" );
document.write( "vertex:(-2,0)<BR>\n" );
document.write( "axis of symmetry: x=-2<BR>\n" );
document.write( "p=3 (distance from vertex to focus or directrix on the axis of symmetry<BR>\n" );
document.write( "4p=12<BR>\n" );
document.write( "Equation of given parabola: (x+2)^2=12y<BR>\n" );
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