document.write( "Question 692628: Hi ok so here's my problem: How many ounces of a 15% acid solution and a 40% acid solution must be mixed together to produce 30 ounces of a 33 1/3 acid soltuion?\r
\n" ); document.write( "\n" ); document.write( "I know how to do it once I have the equation.
\n" ); document.write( "The first equation I had was;
\n" ); document.write( " x+y=30
\n" ); document.write( " .15x+.40y=30(33 1/3) and then you use combination method but when I tried it I didn't get the right answer?
\n" ); document.write( "If you coudl just help me get the equation that would be great thanks so much!
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Algebra.Com's Answer #427059 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Note that \"+33.333+\" in the problem is a percent
\n" ); document.write( "(1) \"+x+%2B+y+=+30+\"
\n" ); document.write( "(2) \"+.15x+%2B+.4y+=+30%2A.333+\"
\n" ); document.write( "(2) \"+15x+%2B+40y+=+1000+\"
\n" ); document.write( "Multiply both sides of (1) by \"+15+\" and
\n" ); document.write( "subtract (1) from (2)
\n" ); document.write( "(2) \"+15x+%2B+40y+=+1000+\"
\n" ); document.write( "(1) \"+-15x+-+15y+=+-450+\"
\n" ); document.write( "\"+25y+=+550+\"
\n" ); document.write( "\"+y+=+22+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+x+%2B+y+=+30+\"
\n" ); document.write( "(1) \"+x+%2B+22+=+30+\"
\n" ); document.write( "(1) \"+x+=+8+\"
\n" ); document.write( "-------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+.15%2A8+%2B+.4%2A22+=+30%2A.333+\"
\n" ); document.write( "(2) \"+1.2+%2B+8.8+=+10+\"
\n" ); document.write( "(2) \"+10+=+10+\"
\n" ); document.write( "OK
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