document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=692522>Question 692522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "two angles are supplementary . if the measure of the larger angle is 20 degrees less than 4 times the measure of the smaller angle , what is the measure of the larger angle ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427030 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L+S=180<BR>\n" );
document.write( "L=4S-20<BR>\n" );
document.write( "(4S-20)+S=180<BR>\n" );
document.write( "5S=180+20<BR>\n" );
document.write( "5S=200/5<BR>\n" );
document.write( "S=40 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "L=4*40-20<BR>\n" );
document.write( "L=160-20<BR>\n" );
document.write( "L=140 DEGREES FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "140+40=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
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