document.write( "Question 692119: Please help me figure out how to graph this ellipse:\r
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document.write( "(4/9)x^2 + 81y^2 = 1\r
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document.write( "I am unsure of what the fist step in this should be. \n" );
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Algebra.Com's Answer #427005 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! figure out how to graph this ellipse: \n" ); document.write( "(4/9)x^2 + 81y^2 = 1 \n" ); document.write( "standard form of equation for an ellipse with horizontal major axis: \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "standard form of equation for an ellipse with vertical major axis: \n" ); document.write( " \n" ); document.write( "note: a and b interchanged \n" ); document.write( "... \n" ); document.write( "To graph given ellipse: \n" ); document.write( "The first step is to write the equation in standard form for an ellipse \n" ); document.write( "(4/9)x^2 + 81y^2 =1 \n" ); document.write( " \n" ); document.write( "note the absence of h and k, so center is at (0,0) \n" ); document.write( "a^2=9/4 \n" ); document.write( "b^2=1/81 \n" ); document.write( "a>b, so ellipse has a horizontal major axis \n" ); document.write( "... \n" ); document.write( "a^2=9/4 \n" ); document.write( "a=√(9/4)=3/2 \n" ); document.write( "vertices: (0±a,0)=(0±3/2,0)=(-3/2,0) and (3/2,0) (end points of horizontal major axis or x intercepts) \n" ); document.write( "b^2=1/81 \n" ); document.write( "b=√(1/81)=1/9 \n" ); document.write( "co-vertices: (0,0±b)=(0,0±1/9)=(0,-1/9) and (0,1/9) (end points of minor axis or y intercepts) \n" ); document.write( ".. \n" ); document.write( "you now have the center(0,0), vertices(-3/2,0) and (3/2,0) and co-vertices(0,-1/9) and (0,1/9) \n" ); document.write( "with which you can draw the graph \n" ); document.write( " |