document.write( "Question 692384: I need with a Linear Equations Word problem in Algebra 1. Here it is:
\n" ); document.write( "One pipe can be used to fill a tank in 48 min and another can be used to fill it in 1 hour and 12 min. How long will it take to fill the tank if both pipes are used.
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Algebra.Com's Answer #426995 by ankor@dixie-net.com(22740)\"\" \"About 
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One pipe can be used to fill a tank in 48 min and another can be used to fill it in 1 hour and 12 min.
\n" ); document.write( " How long will it take to fill the tank if both pipes are used.
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\n" ); document.write( "Convert 1 hr 12 min, to min: 60 + 12 = 72 min
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\n" ); document.write( "Let t = time (in min) to fill the tank using both pipes
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\n" ); document.write( "Let the competed job = 1; (a full tank)
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\n" ); document.write( "Each pipe will do a fraction of the job, the two fractions add up to 1
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\n" ); document.write( "\"t%2F48\" + \"t%2F72\" = 1
\n" ); document.write( "Multiply by the least common multiple to clear the denominators
\n" ); document.write( "144*\"t%2F48\" + 144*\"t%2F72\" = 144
\n" ); document.write( "cancel the denominators and you have
\n" ); document.write( "3t + 2t = 144
\n" ); document.write( "5t = 144
\n" ); document.write( "t = 144/5
\n" ); document.write( "t = 28.8 min working together
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\n" ); document.write( "Check this using a calc
\n" ); document.write( "\"28.8%2F48\" + \"28.8%2F72\" =
\n" ); document.write( ".6 + .4 = 1; confirms our solution to 28.8
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