document.write( "Question 692420: 3x+2y+z=3
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document.write( "x-3y+z=4
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document.write( "-6-4y-2z=1
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document.write( "I started the problem but can't seem to advance\r
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document.write( "3x+2y+z=3
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document.write( "x-3y+z=4\r
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document.write( "2x+5y=-1 \n" );
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Algebra.Com's Answer #426994 by Alan3354(69443) You can put this solution on YOUR website! 3x+2y+z=3 \n" ); document.write( "x-3y+z=4 \n" ); document.write( "-6-4y-2z=1 \n" ); document.write( "--------------- \n" ); document.write( "There's no x term in the 3rd eqn \n" ); document.write( "--- \n" ); document.write( "If you meant: \n" ); document.write( "3x+2y+z=3 \n" ); document.write( "x-3y+z=4 \n" ); document.write( "-6x-4y-2z=1 \n" ); document.write( "then eqn 3 is 2 times eqn 1, but the RH side is different --> inconsistent \n" ); document.write( "No solution. \n" ); document.write( "Eqn's 1 & 3 give parallel planes in 3-space, no intersection. \n" ); document.write( " \n" ); document.write( " |