document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=692383>Question 692383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PART 1: The graph of the equation y^2-x^2+2x=2 is:<BR>\n" );
document.write( "PART 2: The graph of the equation y-x^2=2x\r<BR>\n" );
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document.write( "a. parabola<BR>\n" );
document.write( "b. elipse<BR>\n" );
document.write( "c. circle<BR>\n" );
document.write( "d. hyperbola<BR>\n" );
document.write( "e. none of these\r<BR>\n" );
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document.write( "Part 1 Solve:<BR>\n" );
document.write( "y^2-x^2+2x=2<BR>\n" );
document.write( "???????????\r<BR>\n" );
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document.write( "Part 2 Solve:<BR>\n" );
document.write( "y-x^2=2x<BR>\n" );
document.write( "y=x^2+2x<BR>\n" );
document.write( "(parabola) \r<BR>\n" );
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document.write( "That's all I got, I don't know how I would solve part 1 to figure out what kind it is and I'm pretty sure part 2 is right. If anyone can solve part 1 it would help a lot </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426989 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PART 1: The graph of the equation y^2-x^2+2x=2 is:<BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "y^2-x^2+2x=2<BR>\n" );
document.write( "y^2-(x^2-2x+1)=2-1<BR>\n" );
document.write( "y^2-(x-1)^2=1<BR>\n" );
document.write( "This is an equation of a hyperbola with vertical transverse axis and center at (1,0)<BR>\n" );
document.write( "Its standard form: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1 ALIGN=MIDDLE  ALT=\"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, (h,k)=(x,y) coordinates of center<BR>\n" );
document.write( "..<BR>\n" );
document.write( "PART 2: The graph of the equation y-x^2=2x <BR>\n" );
document.write( "complete the square:<BR>\n" );
document.write( "y-x^2=2x<BR>\n" );
document.write( "y-x^2-2x=0<BR>\n" );
document.write( "y-(x^2+2x+1)=0-1<BR>\n" );
document.write( "y-(x+1)^2=-1<BR>\n" );
document.write( "(x+1)^2=y+1<BR>\n" );
document.write( "This is an equation of a parabola that opens upwards.<BR>\n" );
document.write( "Its standard form: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2=4p%28y-k%29 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2=4p%28y-k%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, (h,k)=(x,y) coordinates of the vertex\r<BR>\n" );
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document.write( "note: Often the best way to see what conic the given equation is, write it in standard form by completing the square. </SPAN>\n" );
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