document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=692367>Question 692367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 7 cm longer than it is wide. its perimeter is at least 58 cm. what are the smallest possible dimensions for the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426978 by </B><A HREF=/tutors/aboutme.mpl?userid=partha_ban><B>partha_ban(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=partha_ban><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=partha_ban><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w = width<BR>\n" );
document.write( "Then length = w + 7<BR>\n" );
document.write( "Therefore, 2(length + width) = 58<BR>\n" );
document.write( "2(w+7+w) = 58<BR>\n" );
document.write( "w + 7 + w = 58/2 = 29<BR>\n" );
document.write( "2w + 7 = 29<BR>\n" );
document.write( "2w = 29 - 7 = 22<BR>\n" );
document.write( "w = 22/2 = 11<BR>\n" );
document.write( "Therefore width = 11 cm and length = 11+7 = 18 cm </SPAN>\n" );
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