document.write( "Question 691774: solve for x
\n" ); document.write( "a) 32^x+4=8^3x-2 \n" ); document.write( "

Algebra.Com's Answer #426907 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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solve for x
\n" ); document.write( "Assume the problem is:
\n" ); document.write( "a) $\"32%5E%28%28x%2B4%29%29+=+8%5E%28%283x-2%29%29\"$
\n" ); document.write( "32 = 2^5, and 8 = 2^3, therefore we can write this
\n" ); document.write( " $\"2%5E%285%28x%2B4%29%29+=+2%5E%283%283x-2%29%29\"$
\n" ); document.write( "if the base is equal the exponents are equal, write it:
\n" ); document.write( "5(x+4) = 3(3x-2)
\n" ); document.write( "5x + 20 = 9x - 6
\n" ); document.write( "20 + 6 = 9x - 5x
\n" ); document.write( "26 = 4x
\n" ); document.write( "x = 26/4
\n" ); document.write( "x = 6.5
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this on your calc, enter both, compare the results
\n" ); document.write( "32^(6.5+4)
\n" ); document.write( "and
\n" ); document.write( "8^(3(6.5)-2)
\n" ); document.write( " \n" ); document.write( "

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