document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61910>Question 61910</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321227573/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me with this one please<BR>\n" );
document.write( "         2-5x     x+4 <BR>\n" );
document.write( "Solve 16^     =64^<BR>\n" );
document.write( "16 to the power of 2-5x=64 to power of x+4<BR>\n" );
document.write( "thank you for your time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42690 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given expression is: \r<BR>\n" );
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document.write( "16^(2 - 5x) = 64^(x + 4) \r<BR>\n" );
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document.write( "16 can be written as 4^2 and 64 can be written as 4^3.\r<BR>\n" );
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document.write( "Hence, the above expression becomes:\r<BR>\n" );
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document.write( "4<sup>2(2 - 5x)</sup> = 4<sup>3(x + 4)</sup> \r<BR>\n" );
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document.write( "Since, the bases are same, we equate the powers.\r<BR>\n" );
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document.write( "2(2 - 5x) = 3(x + 4) \r<BR>\n" );
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document.write( "4 - 10x = 3x + 12 \r<BR>\n" );
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document.write( "0 = 8 + 13x\r<BR>\n" );
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document.write( "13x = - 8 \r<BR>\n" );
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document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-8%2F13 ALIGN=MIDDLE  ALT=\"-8%2F13\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Hence, the solution. </SPAN>\n" );
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