document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=691924>Question 691924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I think this is more Precalculus;<BR>\n" );
document.write( "Triangle ABC is a right triangle with an angle of C=90 degrees. Length AC= 3 square root 3, and angle B= 30 deg. \r<BR>\n" );
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document.write( "Find AB and BC. \r<BR>\n" );
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document.write( "I cant seem to figure it out even though I drew what I read.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426891 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you draw out a triangle, you'll see that AC is opposite the 30 degree angle.\r<BR>\n" );
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document.write( "So AC is the shortest leg.\r<BR>\n" );
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document.write( "The hypotenuse is twice the shortest leg, so the hypotenuse is 6*sqrt(3) units long. \r<BR>\n" );
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document.write( "So AB = 6*sqrt(3)\r<BR>\n" );
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document.write( "The longer leg is sqrt(3) times the shortest leg, so the longer leg is 9 units long. This is because 3*sqrt(3) times sqrt(3) = 3*srt(3*3) = 3*sqrt(9) = 3*3 = 9\r<BR>\n" );
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document.write( "So BC = 9 </SPAN>\n" );
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