document.write( "Question 691001: three plants manufacture light bulb. plant 1 manufactures 40% of the light bulbs, plant 2 manufactures 35% of the light bulbs and plant 3 manufactures 25% of the light bulbs. at plant 1, 10 out of every 100 bulbs is defective, plant 2, 13 out of every 100 bulbs is defective, plant 3, 20 out of every 100 bulbs is defective. what is the probability that a costumer that purchases a bulb from dims factory buys one defective? \n" ); document.write( "
Algebra.Com's Answer #426890 by KMST(5328)\"\" \"About 
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We could start based on a total of \"x\" bulbs manufactured,
\n" ); document.write( "but we can calculate based on any total number of bulbs manufactured,
\n" ); document.write( "and the ratios would be the same anyway.
\n" ); document.write( "(I will choose 2000 because that gives me nice round numbers).
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\n" ); document.write( "For every \"2000\" bulbs manufactured, the following is true:
\n" ); document.write( "Plant #1 makes \"0.40%2A2000=800\" bulbs (40% of \"2000\"), including
\n" ); document.write( "\"%2810%2F100%29%2A800=80\" defective bulbs.
\n" ); document.write( "Plant #2 makes \"0.35%2A2000=700\" bulbs (35% of \"2000\"), including
\n" ); document.write( "\"%2813%2F100%29%2A700=101\" defective bulbs.
\n" ); document.write( "Plant #3 makes \"0.25%2A2000=500\" bulbs (25% of \"2000\"), including
\n" ); document.write( "\"%2820%2F100%29%2A500=100\" defective bulbs.
\n" ); document.write( "
\n" ); document.write( "Out of a total of \"2000\" bulbs, \"80%2B101%2B100=281\" bulbs are defective.
\n" ); document.write( "A customer who buys one bulb from that company has a
\n" ); document.write( "\"281%2F2000\" (or 14.05%) probability of getting a defective bulb.
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