document.write( "Question 61960: log34xlog34x = 5 \n" ); document.write( "
Algebra.Com's Answer #42687 by chitra(359)\"\" \"About 
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The given expression is: \r
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\n" ); document.write( "\n" ); document.write( "log34xlog34x = 5\r
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\n" ); document.write( "\n" ); document.write( "This can be written as: \r
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\n" ); document.write( "\n" ); document.write( "(log34x)(log34x) = 5 \r
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\n" ); document.write( "\n" ); document.write( "==> (log34x)^2 = 5 \r
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\n" ); document.write( "\n" ); document.write( "Taking root on both the sides, we get: \r
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\n" ); document.write( "\n" ); document.write( "(log34x) = \"sqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using the definition of log, we get: \r
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\n" ); document.write( "\n" ); document.write( "3\"sqrt%285%29\" = 4x \r
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\n" ); document.write( "\n" ); document.write( "(3\"sqrt%285%29\"/4) = x \r
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\n" ); document.write( "\n" ); document.write( "Hence, the solution.. \r
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