document.write( "Question 691732: Write an equation of the form f(x)=ax^2+bx+c in which f(0)= -6 f(2)= -3 and f(4)=2\r
\n" ); document.write( "\n" ); document.write( "I found out that c is -6, I tried using the sum and product of roots but I can't figure it out, please help?
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Algebra.Com's Answer #426835 by sachi(548)\"\" \"About 
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f(x)=ax^2+bx+c
\n" ); document.write( " f(0)= -6
\n" ); document.write( "or a*0+b*0+c=-6
\n" ); document.write( "or c=-6 .............1
\n" ); document.write( "f(2)= -3
\n" ); document.write( "or a*2^2+b*2+c =-3
\n" ); document.write( "or 4a+2b-6=-3
\n" ); document.write( "or 4a+2b=6-3=3.......2
\n" ); document.write( "f(4)=2
\n" ); document.write( "a*4^2+b*4+c =2
\n" ); document.write( "or 16a+4b-6=2
\n" ); document.write( "or 16a+4b=6+2=8
\n" ); document.write( "or 4a+b=8/4=2.......3
\n" ); document.write( "subtracting eqn 3 from eqn 2
\n" ); document.write( "4a+2b=3
\n" ); document.write( "4a+b=2
\n" ); document.write( "- - -
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\n" ); document.write( "b=1
\n" ); document.write( "putting this in eqn 2
\n" ); document.write( "4a+2*1=3
\n" ); document.write( "or 4a=3-2=1
\n" ); document.write( "or a=1/4
\n" ); document.write( "so a=1/4,b=1&c=-6
\n" ); document.write( "ans
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