document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61955>Question 61955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of type must be mixed to obtain 400 gallons of a 25% alcohol mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42682 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of type must be mixed to obtain 400 gallons of a 25% alcohol mixture?<BR>\n" );
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document.write( "Let amount of 10% solution be \"x\"; amount of alcohol is 0.10x<BR>\n" );
document.write( "Amount of 35% solution is \"400-x\"; amount of alcohol is 0.35(400-x)=140-0.35x<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "alcohol + alcohol = 0.25(400)<BR>\n" );
document.write( "0.10x+140-0.35x = 100<BR>\n" );
document.write( "-0.25x=-40<BR>\n" );
document.write( "x=160 gallons (amount of 10% solution)<BR>\n" );
document.write( "400-x=240 gallons (amount of 35% solution)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );