document.write( "Question 691679: how long would it take to double an investment of 1000 at 9 percent compounded quarterly? \n" ); document.write( "
Algebra.Com's Answer #426815 by nerdybill(7384)\"\" \"About 
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how long would it take to double an investment of 1000 at 9 percent compounded quarterly?
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\n" ); document.write( "Use:
\n" ); document.write( "A = P(1+i/n)^(nt)
\n" ); document.write( "where
\n" ); document.write( "A is amount after time t (2P)
\n" ); document.write( "P is the principal (P)
\n" ); document.write( "i is the interest per year (.09)
\n" ); document.write( "n is the times compounded during the year (4)
\n" ); document.write( "t is number of years (what we're looking for)
\n" ); document.write( ".
\n" ); document.write( "A = P(1+i/n)^(t/n)
\n" ); document.write( "2P = P(1+.09/4)^(4t)
\n" ); document.write( "2 = (1+.09/4)^(4t)
\n" ); document.write( "2 = (1.0225)^(4t)
\n" ); document.write( "\"log%281.0225%2C2%29\" = 4t
\n" ); document.write( "\"log%281.0225%2C2%29%2F4\" = t
\n" ); document.write( "7.79 years = t
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