document.write( "Question 691679: how long would it take to double an investment of 1000 at 9 percent compounded quarterly? \n" ); document.write( "
Algebra.Com's Answer #426815 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! how long would it take to double an investment of 1000 at 9 percent compounded quarterly? \n" ); document.write( ". \n" ); document.write( "Use: \n" ); document.write( "A = P(1+i/n)^(nt) \n" ); document.write( "where \n" ); document.write( "A is amount after time t (2P) \n" ); document.write( "P is the principal (P) \n" ); document.write( "i is the interest per year (.09) \n" ); document.write( "n is the times compounded during the year (4) \n" ); document.write( "t is number of years (what we're looking for) \n" ); document.write( ". \n" ); document.write( "A = P(1+i/n)^(t/n) \n" ); document.write( "2P = P(1+.09/4)^(4t) \n" ); document.write( "2 = (1+.09/4)^(4t) \n" ); document.write( "2 = (1.0225)^(4t) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "7.79 years = t \n" ); document.write( " \n" ); document.write( " |