document.write( "Question 691313: find vertex, focus, and equation of directrix of y^2 = 36x \n" ); document.write( "
Algebra.Com's Answer #426791 by lwsshak3(11628)\"\" \"About 
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find vertex, focus, and equation of directrix of y^2 = 36x
\n" ); document.write( "This is an equation of a parabola that opens rightwards.
\n" ); document.write( "Its standard form of equation: (y-k)=4p(x-h), (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "For given equation: y^2=36x
\n" ); document.write( "vertex:(0,0)
\n" ); document.write( "axis of symmetry: y=0 or x-axis
\n" ); document.write( "4p=36
\n" ); document.write( "p=9
\n" ); document.write( "focus: (9,0) (p-distance to the right of the vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=9 (p-distance to the left of the vertex on the axis of symmetry)
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