document.write( "Question 691410: The sum of the digits of a two digit number is 1. The number formed by reversing the number is 4 less than 5 times the number. Find the original number?\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out with this question I really don't understand? thanks in advance.
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Algebra.Com's Answer #426740 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let a = the 10's digit
\n" ); document.write( "let b = the ones
\n" ); document.write( "then
\n" ); document.write( "10a+b = the two digit number
\n" ); document.write( "and
\n" ); document.write( "10b+a = the number with reversed digits
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"The sum of the digits of a two digit number is 1,\" indicates that something is wrong as written, no two positive integers are equal to 1
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\n" ); document.write( "Try to solve it without knowing the sum of the digits
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\n" ); document.write( " The number formed by reversing the number is 4 less than 5 times the number.
\n" ); document.write( "10b + a = 5(10a+b) - 4
\n" ); document.write( "10b + a = 50a + 5b - 4
\n" ); document.write( "10b - 5b = 50a - a - 4
\n" ); document.write( "5b = 49a - 4
\n" ); document.write( "Divide both sides by 9
\n" ); document.write( "b = \"49%2F5\"a - \"4%2F5\"
\n" ); document.write( "A little thought here reveals that if a = 1, we have
\n" ); document.write( "b = \"49%2F5\" - \"4%2F5\"
\n" ); document.write( "b = \"45%2F5\"
\n" ); document.write( "b = 9
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\n" ); document.write( "a = 1, is the only value that makes b an integer
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\n" ); document.write( "Our number is 19
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\n" ); document.write( "Check this in the statement:
\n" ); document.write( "\"The number formed by reversing the number is 4 less than 5 times the number.\"
\n" ); document.write( "91 = 5(19) - 4
\n" ); document.write( "91 = 95 - 4
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\n" ); document.write( "The 1st statement should have read
\n" ); document.write( "The sum of the digits is 10\r
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