document.write( "Question 691497: graph the ellipse showing proper algebra
\n" ); document.write( "6x^2+y^2=36
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Algebra.Com's Answer #426725 by MathLover1(20850)\"\" \"About 
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\"6x%5E2%2By%5E2=36\"......both sides divide by \"36\"\r
\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2F36%2By%5E2%2F36=36%2F36\".\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F6%2By%5E2%2F36=1\".............since there is no \"h\" and \"k\", both are equal to zero, so \r
\n" ); document.write( "\n" ); document.write( "the center is at (\"0\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=36\".....major axis is vertical and \"b%5E2=6\" is horizontal axis\r
\n" ); document.write( "\n" ); document.write( "the length of \"a=6\" and \"a=-6\" \r
\n" ); document.write( "\n" ); document.write( "\"b=sqrt%286%29=2.5\"\r
\n" ); document.write( "\n" ); document.write( "the length of \"b=2.5\" and \"b=-2.5\"\r
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\n" ); document.write( "\n" ); document.write( "Center: (h, k)=(0, 0)\r
\n" ); document.write( "\n" ); document.write( "Vertices: (0, 6) or (0,-6)\r
\n" ); document.write( "\n" ); document.write( "Foci: (0, 5.5) or (0,-5.5)\r
\n" ); document.write( "\n" ); document.write( "Co-vertices: (0 ± 2.5, 2.5) or (2.5,0), and (-2.5,0)\r
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\n" ); document.write( "\n" ); document.write( "Length of Major Axis: 2a=12\r
\n" ); document.write( "\n" ); document.write( "Length of Minor Axis: 2b=5\r
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