document.write( "Question 691424: The unit cost in dollars for manufacturing IPODS is given by C(n)=0.004n^2-3.2n +660. what is the minimum cost? \n" ); document.write( "
Algebra.Com's Answer #426716 by mouk(232)\"\" \"About 
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Let \"+C=0.004n%5E2-3.2n+%2B660+\"
\n" ); document.write( "then \"+dC%2Fdn+=+%282%29%280.004n%5E1%29+-+3.2+=+0.008n+-+3.2+\"\r
\n" ); document.write( "\n" ); document.write( "Critical values occur when \"+dC%2Fdn+=+0+\"
\n" ); document.write( "so, \"+0.008n+-+3.2+=+0+\"
\n" ); document.write( "\"+0.008n+=+3.2+\"
\n" ); document.write( "\"+n+=+3.2%2F0.008+=+400+\"\r
\n" ); document.write( "\n" ); document.write( "Does \"+n+=+400+\" correspond to a max or min?\r
\n" ); document.write( "\n" ); document.write( "Look at the second derivative:
\n" ); document.write( "\"+dC%2Fdn+=+0.008n+-+3.2+\" so then \"+d%5E2C%2Fdn%5E2+=+0.008+\"
\n" ); document.write( "which is +ve so critical point is a MINIMUM\r
\n" ); document.write( "\n" ); document.write( "Hence, minimum cost occurs when \"+n+=+400+\" so minimum cost is found by putting \"+n+=+400+\" in original equation\r
\n" ); document.write( "\n" ); document.write( "Giving minimum cost = 20
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