document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=691394>Question 691394</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 7 cm less than its length and its area is 250cm. Find its dimmensions*you may use any method.\r<BR>\n" );
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document.write( "so what I tried doing is let X represent the length and do 250 equals (x-7)*7 but I feel like this is super wrong. Please help. Thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426715 by </B><A HREF=/tutors/aboutme.mpl?userid=mouk><B>mouk(232)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mouk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mouk><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Nearly correct !\r<BR>\n" );
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document.write( "Let length=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x+ ALIGN=MIDDLE  ALT=\"+x+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then width=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-7 ALIGN=MIDDLE  ALT=\"x-7\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Area = 250 so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x+%28x-7%29+=+250+ ALIGN=MIDDLE  ALT=\"+x+%28x-7%29+=+250+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Expanding gives:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2+-+7x+=+250+ ALIGN=MIDDLE  ALT=\"+x%5E2+-+7x+=+250+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2+-+7x+-+250+=+0+ ALIGN=MIDDLE  ALT=\"+x%5E2+-+7x+-+250+=+0+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Solving using the quadratic formula gives:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%287+%2B-+sqrt%28+49%2B1000+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%287+%2B-+sqrt%28+49%2B1000+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-12.69+ ALIGN=MIDDLE  ALT=\"x+=+-12.69+\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+19.69+ ALIGN=MIDDLE  ALT=\"x+=+19.69+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (working to 2dp)<BR>\n" );
document.write( "Obviously as x is the length then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%3E0+ ALIGN=MIDDLE  ALT=\"x+%3E0+\"   DISABLED_style= \"max-width:90%; height:auto;\" > so solution is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+19.69+ ALIGN=MIDDLE  ALT=\"x+=+19.69+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
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